linux script

[hosted]

Is there a linux script to pull the provisioning password per domain? (like the password script)

[Vodia PBX]

Is there a linux script to pull the provisioning password per domain? (like the password script)

 

So far no. But the http://kiwi.pbxnsip.com/index.php/Password_Overview (sorry I can't find it in the knowledge database) should be a very good template for this.

[pbxuser911]

is it possible to be able to also add that it should include the Domain name in the results when using the following script

 

#!/bin/bash
# Show the passwords of all users:

function get_xml()
{
 gawk -v tag=$1 'BEGIN{regex="<" tag ">([^<]*)</" tag ">";}{ match($0, regex, m); for(i = 1;; i++) { if(!(i in m)) break; printf("%s\n",m[i]);}}' $2
}

for user in users/*.xml
do
 name=${user:6} # only the name
 idx=${name%.xml} # only the number
 type=$(get_xml type $user)
 if [ "$type" == extensions ]; then
id=$(get_xml id $user)
primary=$(get_xml alias $user)
dialplan=$(get_xml dial_plan $user)
if [ -z "$dialplan" ]; then
  plan="Default"
else
  plan=$(get_xml name dial_plan/$dialplan.xml)
fi
password=$(get_xml password extensions/$id.xml)
pin=$(get_xml mb_pin extensions/$id.xml)
username=$(get_xml name user_alias/$primary.xml)
if [ -z "$pin" ]; then
  echo $username $password \($plan\)
else
  echo $username $password \($plan\) [$pin]
fi
 fi
done

[pbx support]

is it possible to be able to also add that it should include the Domain name in the results when using the following script

 

This should do the domain name

 

#!/bin/bash
# Show the passwords of all users:

function get_xml()
{
 gawk -v tag=$1 'BEGIN{regex="<" tag ">([^<]*)</" tag ">";}{ match($0, regex, m); for(i = 1;; i++) { if(!(i in m)) break; printf("%s\n",m[i]);}}' $2
}

for user in users/*.xml
do
 name=${user:6} # only the name
 idx=${name%.xml} # only the number
 type=$(get_xml type $user)
 if [ "$type" == extensions ]; then
id=$(get_xml id $user)
primary=$(get_xml alias $user)
	domain=$(get_xml domain user_alias/$primary.xml)
	for d in domain_alias/*.xml
	do
	  dom=$(get_xml domain $d)
	  if [ -z "$dom" -a "$dom" == "$domain" ]; then
		domain_name=$(get_xml name $d)
	  break
	  fi
	done

dialplan=$(get_xml dial_plan $user)
if [ -z "$dialplan" ]; then
  plan="Default"
else
  plan=$(get_xml name dial_plan/$dialplan.xml)
fi
password=$(get_xml password extensions/$id.xml)
pin=$(get_xml mb_pin extensions/$id.xml)
username=$(get_xml name user_alias/$primary.xml)
if [ -z "$pin" ]; then
  echo $username $password \($plan\)
else
  echo $username $password \($plan\) [$pin]
fi
 fi
done

[pbxuser911]

doesnt show the domain name

also it works much slower then the original code, this one takes time in between the results

[pbxuser911]

doesnt show the domain name

also it works much slower then the original code, this one takes time in between the results

[pbx support]

doesnt show the domain name

also it works much slower then the original code, this one takes time in between the results

 

If you echo the 'domain_name', it will show the domain name.

It will be slower (depending on the number of accounts and/or number of domain) because, it has to run another loop for every account.

[pbxuser911]

can you write that script and post it? i am not familiar with how to write the scripts

[pbxuser911]

ok, i added the following codes, but it only shows the domain alias, not the full name

also its extremely slow, the one i posted on top was much quicker

 

#!/bin/bash
# Show the passwords of all users:

function get_xml()
{
 gawk -v tag=$1 'BEGIN{regex="<" tag ">([^<]*)</" tag ">";}{ match($0, regex, m); for(i = 1;; i++) { if(!(i in m)) break; printf("%s\n",m[i]);}}' $2
}

for user in users/*.xml
do
 name=${user:6} # only the name
 idx=${name%.xml} # only the number
 type=$(get_xml type $user)
 if [ "$type" == extensions ]; then
id=$(get_xml id $user)
primary=$(get_xml alias $user)
	domain=$(get_xml domain user_alias/$primary.xml)
	for d in domain_alias/*.xml
	do
	  dom=$(get_xml domain $d)
	  if [ -z "$dom" -a "$dom" == "$domain" ]; then
		domain_name=$(get_xml name $d)
	  break
	  fi
	done

dialplan=$(get_xml dial_plan $user)
if [ -z "$dialplan" ]; then
  plan="Default"
else
  plan=$(get_xml name dial_plan/$dialplan.xml)
fi
password=$(get_xml password extensions/$id.xml)
pin=$(get_xml mb_pin extensions/$id.xml)
username=$(get_xml name user_alias/$primary.xml)
if [ -z "$pin" ]; then
  echo $domain $username $password \($plan\)
else
  echo $domain $username $password \($plan\) [$pin]
fi
 fi
done

[pbxuser911]

can anyone onhere that knows linux write the shell script that will show the all the passwords for all domains and accounts, but also include which domain it is for?

[hosted]

I always made the first 3 characters represent the domain then the remainder are random. so when I run the script I see what domain..

 

thats the extent of my hack/scripting skills.

[pbxuser911]

can you share the script?

[hosted]

I just use the one posted in the wiki.

 

yea that script above is pretty CPU intense. nice -19 i say